-b^2-46b=240

Solution for -b^2-46b=240 equation:

-b^2-46b=240

We move all terms to the left:

-b^2-46b-(240)=0

We add all the numbers together, and all the variables

-1b^2-46b-240=0

a = -1; b = -46; c = -240;
Δ = b2-4ac
Δ = -462-4·(-1)·(-240)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-34}{2*-1}=\frac{12}{-2}
=-6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+34}{2*-1}=\frac{80}{-2}
=-40
$